Mocking methods of abstract classes

[Krzysztof-Lempicki]

Hi,

I have class:

abstract class MyClass {

      void doSomething() {
          method1()
          method2() 
      }

     abstract void method1()
     abstract void method2()

}

Is this possible with spock to run test in this manner:

    ...
    MyClass mc = Mock / Spy

    ... 
    then:
    1* mc.method1()

?

I am aware that:

• in design I can replace abstract method with field of interface type and call it directly in doSomething body
• I can create test impl of this abstract class

I want to know if what I want to achieve is possible without above solutions.

[AndreasTu]

You would write someting like this when you want to use a Spy:

  def "Spy of abstract class"() {
    given:
    AbstractClass mc = Spy()
    when:
    mc.doSomething()

    then:
    //The >> null are here required to override the default Spy behavior, which would answer with a non existing method.
    1 * mc.method1() >> null 
    1 * mc.method2() >> null
  }

Or you can do it with a Mock:

  def "Mockof abstract class"() {
    given:
    AbstractClass mc = Mock() {
      doSomething() >> { callRealMethod() }
    }
    when:
    mc.doSomething()

    then:
    1 * mc.method1()
  }