Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Task.sequentially() #16

Open
rpominov opened this issue Aug 18, 2016 · 2 comments
Open

Task.sequentially() #16

rpominov opened this issue Aug 18, 2016 · 2 comments

Comments

@rpominov
Copy link
Owner

Same signature as in Task.parallel() but runs tasks in sequence.

@rpominov
Copy link
Owner Author

https://github.com/russiann/promise-sequential seems like I'm not the only one who thought about this idea :)

@rpominov rpominov added idea and removed raw idea labels Oct 3, 2016
@danielbom
Copy link

I needed this them I build one function:

function sequenceTasks(tasks) {
  return Task.chainRec((next, done, pair) => {
    const [result, rest] = pair;

    if (rest.length === 0)
      return Task.of(done(result));

    return rest[0].map(x => next([
      result.concat(x),
      rest.slice(1)
    ]));
  }, [[], tasks]);
}

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

No branches or pull requests

2 participants