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Task.sequentially() #16
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https://github.com/russiann/promise-sequential seems like I'm not the only one who thought about this idea :) |
I needed this them I build one function: function sequenceTasks(tasks) {
return Task.chainRec((next, done, pair) => {
const [result, rest] = pair;
if (rest.length === 0)
return Task.of(done(result));
return rest[0].map(x => next([
result.concat(x),
rest.slice(1)
]));
}, [[], tasks]);
} |
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Same signature as in
Task.parallel()
but runs tasks in sequence.The text was updated successfully, but these errors were encountered: