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[BUG] kwargs are not respected #157
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It is perfectly right. This is how argument passing works in Python, even without any decorator. |
I'm sorry - I must be missing something obvious here: If I call func(*a, **k) as func(inputdir='a', tempdir='b), shouldn't a = (), and k = dict(inputdir='a', tempdir='b) ? |
Yes, but you are calling |
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If I just ran the example from the doc:
print(kw)
shows empty dict, which It should not right ?The text was updated successfully, but these errors were encountered: