Using fzf in zx code. Verbose.

[tsekaris]

I use fzf to select a color:

#!/usr/bin/env zx
$.verbose = true
let color = (await $`echo -e "red\nblack\nyellow\nwhite" | fzf`).stdout.trim()
console.log(color);

It works but the ouput is ugly:

$ echo -e "red
> black
> yellow
> white" | fzf
white
white

If i run it with $.verbose = false fzf is not apearing.

How can I change the code so that only fzf is displayed?

[tsekaris]

One ugly solution:

#!/usr/bin/env zx
$.verbose = true
let color = (await $`echo -e "red\nblack\nyellow\nwhite"`.quiet().pipe($`fzf`)).stdout.trim()

function deleteLines (lines = 1) {
    let i = lines
    do {
        i -= 1;
        process.stdout.moveCursor(0, -1) // up one line
        process.stdout.clearLine(1) // from cursor to end
    } while (i > 0)
}
deleteLines(2)

console.log(color)

[antonmedv]

$.verbose = false
....pipe($`fzf`.pipe(process.stdout))

[tsekaris]

I tried your code:

#!/usr/bin/env zx
$.verbose = false
await $`echo -e "red\nblack\nyellow\nwhite"`.pipe($`fzf`.pipe(process.stdout))

Fzf does not appear...

[antonmedv]

Try with stderr. I think fzf renders to stderr.

[tsekaris]

Υou're right. Is working with stderr:

$.verbose = false
let p = $`echo -e "red\nblack\nyellow\nwhite"`.pipe($`fzf`)
p.stderr.pipe(process.stderr)
let color = (await p).stdout.trim()
console.log(color)

Thank you for your time...

[antonmedv]

Also you can do:

echo`color:  ${await p}`