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FirebirdSchema #453

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MrSpockDe opened this issue Jun 5, 2022 · 0 comments
Open

FirebirdSchema #453

MrSpockDe opened this issue Jun 5, 2022 · 0 comments

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@MrSpockDe
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in line 72 of FirebirdSchema.php the compact function tries to add the variable 'parameters' to the array, but there is no such variable. Therefore one cannot define a role for access to a Firebird DB. An error message states that there is an error at a "comapct call".

Change this line to:

$settings = compact('schemaName', 'resourceName', 'name', 'internalName', 'quotedName'); //omit the 'parameters' variable

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