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Question: SwaggerException with TResult #34

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mdmota opened this issue May 3, 2019 · 2 comments
Open

Question: SwaggerException with TResult #34

mdmota opened this issue May 3, 2019 · 2 comments

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@mdmota
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mdmota commented May 3, 2019

How do I get the return object from throw new SwaggerException (...) using TResult?
I need the deserialized object in return

@mdmota
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mdmota commented May 3, 2019

My error and success return objects are of the same type

@unchase
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unchase commented May 4, 2019

For example, in this way?

try
{ 

}
catch (SwaggerException ex)
{
    //if (ex.StatusCode != 200) // you can check statusCode
    return JsonConvert.DeserializeObject<TResult>(ex.Response, new JsonSerializerSettings());
}

or

try
{ 

}
catch (SwaggerException<TResult> ex)
{
    //if (ex.StatusCode != 200) // you can check statusCode
    return ex.Result;
}

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