conditional if() validation does not allow late type matching

[adrienjoly]

I was expected the following validation code to work, based on https://github.com/bodinsamuel/altheia/blob/master/Documentation.md#if-test-func-then-func-otherwise-func- and https://github.com/bodinsamuel/altheia/blob/master/test/base.test.js#L133:

  alt.any().if({
    test: test => test.array(),
    then: test =>
      test
        .array()
        .min(1)
        .oneOf(alt.string()),
    otherwise: test => test.boolean(),
  }),

... but the test => test.array() expression ends up throwing a test.array is not a function error.

I'm guessing that any() should return an object that still allows type checking methods like array().

[bodinsamuel]

Thanks for the report !

You are right that the chaining imply same type but it's optional, this should work better:

 alt.any().if({
  test: () => alt.array(),
  then: () => alt.array().min(1).oneOf(alt.string()),
  otherwise: () => alt.boolean(),
})

Anyway this if is poorly design. I will create a better oneOf for all types that should cover all use cases.