-
|
I'm having a bit of trouble linking This is the error I get: It seems And Any pointers on where I'm going wrong is greatly appreciated 🙏. Snippet from my cmake file: # ryml
FetchContent_Declare(ryml
GIT_REPOSITORY https://github.com/biojppm/rapidyaml.git
GIT_TAG v0.4.1
GIT_SHALLOW FALSE
)
FetchContent_MakeAvailable(ryml)
add_executable(example EXCLUDE_FROM_ALL
main.cpp
)
target_link_libraries(example
PRIVATE ryml::ryml
)Basic code I'm trying to compile: #include <iostream>
#include <fstream>
#include <vector>
#include <ryml.hpp>
int main() {
std::ifstream f("conf.yaml", std::ios::binary);
std::vector<char> buf(8196, 0); // 8k buffer
std::string data;
while(f.good()) {
f.read(buf.data(), buf.size());
std::streamsize s = f.gcount();
std::cout << "read " << s << " bytes" << std::endl;
data += std::string(buf.data());
}
std::cout << "\n --- data --- \n" << data << "\n";
ryml::Tree tree = ryml::parse_in_place(ryml::to_substr(data));
}Output from cmake build generation: |
Beta Was this translation helpful? Give feedback.
Answered by
biojppm
Jul 3, 2022
Replies: 1 comment 1 reply
-
|
You need to include ryml_std.hpp. This is explained in the quick start sample. |
Beta Was this translation helpful? Give feedback.
1 reply
-
|
Silly me, I only read it as being an optional header 🤦♂️. For reference it's explained here: rapidyaml/samples/quickstart.cpp Line 33 in ff54931 |
Beta Was this translation helpful? Give feedback.
Answer selected by
uatuko
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
You need to include ryml_std.hpp. This is explained in the quick start sample.