-
Notifications
You must be signed in to change notification settings - Fork 21
/
SymmetricTree.swift
55 lines (46 loc) 路 1.32 KB
/
SymmetricTree.swift
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
//
// SymmetricTree.swift
// LeetCode
//
// Created by 榛庤档澶儙 on 15/02/2018.
// Copyright 漏 2018 lizhaotailang. All rights reserved.
//
// Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
//
// For example, this binary tree [1,2,2,3,4,4,3] is symmetric:
//
// 1
// / \
// 2 2
// / \ / \
// 3 4 4 3
// But the following [1,2,2,null,3,null,3] is not:
// 1
// / \
// 2 2
// \ \
// 3 3
// Note:
// Bonus points if you could solve it both recursively and iteratively.
//
// Accepted. See [SymmetricTreeTests](./LeetCodeTests/SymmetricTreeTests.swift) for test cases.
//
import Foundation
class SymmetricTree {
func isSymmetric(_ root: TreeNode?) -> Bool {
return isMirror(root, root)
}
func isMirror(_ node1: TreeNode?, _ node2: TreeNode?) -> Bool {
return node1 == nil && node2 == nil || node1 != nil && node2 != nil && (node1!.val == node2!.val) && isMirror(node1!.right, node2!.left) && isMirror(node1!.left, node2!.right)
}
public class TreeNode {
public var val: Int
public var left: TreeNode?
public var right: TreeNode?
public init(_ val: Int) {
self.val = val
self.left = nil
self.right = nil
}
}
}