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ReverseInteger.swift
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ReverseInteger.swift
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//
// ReverseInteger.swift
// LeetCode
//
// Created by 榛庤档澶儙 on 25/11/2017.
// Copyright 漏 2017 lizhaotailang. All rights reserved.
//
// Given a 32-bit signed integer, reverse digits of an integer.
//
// Example 1: Input: 123, Output: 321
// Example 2: Input: -123, Output: -321
//
// Have you thought about this?
// Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
// If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.
// Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows.
// How should you handle such cases?
// For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
//
// Note:
// Assume we are dealing with an environment which could only hold integers within the 32-bit signed integer range.
// For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
//
// Accepted. See [ReverseIntegerTests](./LeetCode/ReverseIntegerTests.swift) for test cases.
//
import Foundation
class ReverseInteger {
func reverse(_ x: Int) -> Int {
if x == 0 {
return 0
}
var result = 0
var anotherX = x
while anotherX != 0 {
result = result * 10 + anotherX % 10
anotherX /= 10
}
let intMax = 2147483647
let intMin = -2147483648
if (result > 0 && (result - intMax) > 0) || (result < 0 && (result - intMin) < 0) {
return 0
}
return Int(result)
}
}