Program to Print Armstrong Numbers Between 1 to 1000

Example:

       153
   13 + 53 + 33
1 + 125 + 27 = 153
Approach :
Count the number of digits in the number.
Then calculate the sum of digits raised to the power of the number of digits in that number.
Check whether it is equal to the number, if yes then print it.

// C Program to Display Armstrong
// numbers between 1 to 1000
#include <stdio.h>
#include <math.h>

int main()
{
	int i, digit1, digit2, digit3, sum, num;
	printf("All Armstrong number between 1 and 1000 are:\n");

	// This loop will run for 1 to 1000
	for (i = 1; i <= 1000; i++)
	{
		num = i;
		// All single digit numbers are Armstrong number.
		if (num <= 9)
		{
			printf("%d ", num);
		}
		else
		{
			sum = pow(num % 10, 3) + pow((num % 100 - num % 10) / 10, 3) + pow((num % 1000 - num % 100) / 100, 3);
			if (sum == i)
			{
				printf("%d ", i);
			}
		}
	}
}