Array-squareUp_b.js

// -------------------------------Description---------------------------------
// This is a question from codingbat

// Given an integer n greater than or equal to 0, create and return an array with the following pattern:

// squareUp(3) => [0, 0, 1, 0, 2, 1, 3, 2, 1]
// squareUp(2) => [0, 1, 2, 1]
// squareUp(4) => [0, 0, 0, 1, 0, 0, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1]
// 0 <= n <= 1000.
// ---------------------------------------------------------------------------

const squareUp = (n) => {
  let result = [];
  for (let i = n; i > 0; i--) {
    for (let j = 1; j <= n; j++) {
      if (j <= i) {
        result.unshift(j);
      } else {
        result.unshift(0);
      }
    }
  }
  return result;
};


// Test cases
console.log(squareUp(3)); // Output: [0, 0, 1, 0, 2, 1, 3, 2, 1]
console.log(squareUp(2)); // Output: [0, 1, 2, 1]
console.log(squareUp(4)); // Output: [0, 0, 0, 1, 0, 0, 2, 1, 0, 3, 2, 1, 4, 3, 2, 1]